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Music technology begins with the physics of sound: what a sound wave is, how frequency and amplitude map onto the pitch and loudness we hear, and how sound behaves in a room. This topic builds the quantitative foundations - the wave equation, the audible range, the decibel and reverberation - and the psychoacoustics that explains why we hear as we do. Every later processor, from EQ to reverb, rests on these ideas, and the numeracy here (metres per second, hertz, decibels, seconds) recurs throughout the written papers.
5 sections~21 min reading time3 competenciesLevel Foundation 1 · Standard 2 · Advanced 2
basic level
The AS-level foundation is what a sound wave is, the audible range, the decibel as a ratio, and the idea of reverberation.
higher level
The full A-level treats these quantitatively - dB calculations, the inverse-square law, RT60 estimation and psychoacoustic effects such as masking - and applies them to production decisions.
Reading depth: In depth
Text size: Standard
A sound wave as pressure against time
The wave equation and period
Wave speed equals frequency times wavelength; period is the reciprocal of frequency.
A loudspeaker reproduces a 100 Hz bass note. Taking the speed of sound in air as 343 m/s, find the wavelength of the note and its period.
Rearrange v = f*lambda to lambda = v/f = 343/100 = 3.43 m.
T = 1/f = 1/100 = 0.010 s = 10 ms.
The 3.43 m wavelength is comparable to room dimensions, which is why low frequencies interact strongly with rooms and are hard to control acoustically.
Result: The 100 Hz note has a wavelength of about 3.4 m and a period of 10 ms.
Typical mistakes
Active revision
A note has a frequency of 440 Hz. Taking the speed of sound as 343 m/s, calculate its wavelength and its period.
Active recall
Recall the key points — then reveal.
Sources: Pearson Edexcel Level 3 Advanced GCE in Music Technology (9MT0) Specification (Pearson Edexcel)
The audible range on a logarithmic frequency axis
An electric bass plays a note with a fundamental of 55 Hz. Give the frequency two octaves higher, and list the first three harmonics of the 55 Hz note.
An octave is a doubling: 55 x 2 = 110 Hz.
Double again: 110 x 2 = 220 Hz, so two octaves above 55 Hz is 220 Hz.
Harmonics are integer multiples of the fundamental: 1st = 55 Hz (the fundamental), 2nd = 110 Hz, 3rd = 165 Hz.
The 2nd harmonic (110 Hz) is exactly one octave up, but the 3rd (165 Hz) is not a whole octave - it is an octave plus a fifth - showing why harmonics and octaves are related but not identical.
Result: Two octaves above 55 Hz is 220 Hz; the first three harmonics are 55, 110 and 165 Hz.
Typical mistakes
Active revision
A note has a fundamental of 110 Hz. Write down the frequencies of its first four harmonics, and state which note lies two octaves above the fundamental.
Active recall
Recall the key points — then reveal.
Sources: Pearson Edexcel Level 3 Advanced GCE in Music Technology (9MT0) Specification (Pearson Edexcel)
The dB SPL scale of everyday sounds
The decibel
Amplitude ratios use a factor of 20; power ratios use a factor of 10 (because power is proportional to amplitude squared).
A pre-amp increases a signal's voltage by a factor of 10. Express this as a gain in decibels. Separately, a singer moves from 0.5 m to 1.0 m from a microphone in the open air; estimate the change in captured level.
Amplitude ratio, so use the factor of 20: gain = 20log10(10) = 201 = 20 dB.
Going from 0.5 m to 1.0 m doubles the distance, so by the inverse-square law the level falls by about 6 dB.
The +20 dB pre-amp gain is a tenfold rise in amplitude, while the -6 dB from doubling the distance is a halving of amplitude - the two are the arithmetic of gain and miking distance.
Result: A x10 voltage gain is +20 dB; doubling the mic distance drops the level by about 6 dB.
Typical mistakes
Active revision
A signal's amplitude is increased by a factor of 4. Express this gain in decibels. Then state the change in dB when a source is moved from 1 m to 4 m away.
Active recall
Recall the key points — then reveal.
Sources: Pearson Edexcel Level 3 Advanced GCE in Music Technology (9MT0) Specification (Pearson Edexcel) · Ofqual - GCE AS and A level qualifications (subject-level conditions and requirements) (Ofqual)
Reverberant decay and RT60
Sabine's equation
V is the room volume in cubic metres; A is the total absorption in square-metre sabins (area times absorption coefficient, summed over all surfaces).
A small studio measures 5 m x 4 m x 3 m (volume 60 cubic metres) and has a total absorption of 20 square-metre sabins. Estimate its reverberation time, then find the absorption needed to halve it.
RT60 = 0.161V/A = 0.16160/20 = 9.66/20 = 0.48 s.
To halve RT60 to 0.24 s, A must double (RT60 is inversely proportional to A), so A must rise from 20 to 40 square-metre sabins.
Adding about 20 more square-metre sabins of absorption (for example soft furnishings or foam panels) would bring the room from a slightly live 0.48 s to a tighter 0.24 s.
Result: The room's RT60 is about 0.48 s; doubling the absorption to 40 sabins would halve it to about 0.24 s.
Typical mistakes
Active revision
A rehearsal room has a volume of 120 cubic metres and a total absorption of 24 square-metre sabins. Use Sabine's equation to estimate its RT60, and state one change that would shorten it.
Active recall
Recall the key points — then reveal.
Sources: Pearson Edexcel Level 3 Advanced GCE in Music Technology (9MT0) Specification (Pearson Edexcel)
Key psychoacoustic effects
In a mix, a bright acoustic guitar strummed high in the arrangement makes the lead vocal sound dull and hard to follow. Explain the psychoacoustic cause and give a solution.
The guitar and the vocal share energy in the upper-mid/presence region (roughly 2-5 kHz), where the ear is most sensitive; the louder guitar masks the vocal in that band.
Because masking works within critical bands, the vocal's intelligibility-carrying presence frequencies are hidden even though its overall level seems adequate.
Carve space with EQ: gently cut the guitar around 2-4 kHz (or dip it under the vocal) so the vocal's presence region is exposed; alternatively pan or arrange the two apart in the stereo field or in time.
Verify at a moderate monitoring level, since the equal-loudness effect changes the balance of presence and bass with volume.
Result: The guitar masks the vocal in the shared, ear-sensitive presence band; cutting the guitar's presence frequencies (or separating them by pan/arrangement) unmasks the vocal.
Typical mistakes
Active revision
Explain why raising the level of a bass guitar in a mix can make the kick drum harder to hear, and describe one EQ or arrangement change that would resolve it.
Active recall
Recall the key points — then reveal.
Sources: Pearson Edexcel Level 3 Advanced GCE in Music Technology (9MT0) Specification (Pearson Edexcel)
References & sources