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How atoms hold together decides everything about a substance's properties. This chapter develops the three chemical bonds - ionic, covalent (including dative) and metallic - and the four types of structure they build, then uses electron-pair repulsion to predict the shapes of molecules and ions, and finishes with electronegativity, polarity and the intermolecular forces that explain melting points, solubility and the strange behaviour of water.
5 sections~17 min reading time3 competenciesLevel Foundation 1 · Standard 3 · Advanced 1
basic level
AS-Level requires the three bond types, the four structures with their properties, electron-pair repulsion shapes and angles, electronegativity, polarity and the three intermolecular forces.
higher level
The full A-Level applies these ideas synoptically - explaining boiling-point trends, solubility, the shapes of transition-metal complexes and the behaviour of organic molecules - so a secure grasp of structure and bonding underpins much of the rest of the course.
Reading depth: In depth
Text size: Standard
Electron transfer forming sodium chloride
Explain why magnesium oxide (mp 2852 C) has a much higher melting point than sodium chloride (mp 801 C).
MgO contains Mg2+ and O2- ions (charges 2+/2-), whereas NaCl contains Na+ and Cl- (charges 1+/1-).
The larger charges in MgO create stronger electrostatic attraction between the ions; Mg2+ and O2- are also smaller than Na+ and Cl-, so the ions pack closer.
Stronger attractions throughout the lattice need more energy to overcome, so MgO melts at a far higher temperature.
Result: The higher ionic charges (and smaller ions) in MgO give much stronger lattice attractions and a higher melting point.
Typical mistakes
Active revision
Magnesium oxide and sodium chloride are both ionic. Explain, using ionic charges and sizes, why magnesium oxide has the higher melting point.
Active recall
Recall the key points — then reveal.
Sources: GCE AS and A level subject content for the sciences (Department for Education) · AQA A-level Chemistry 7405 specification (AQA)
The dative bond in the ammonium ion
Ammonia reacts with a hydrogen ion to form the ammonium ion, NH3 + H+ -> NH4+. Explain how the fourth N-H bond forms and why all four bonds are then identical.
Nitrogen in NH3 has one lone pair of electrons not used in bonding.
This lone pair is donated into the empty 1s orbital of H+, forming a dative covalent bond (both electrons from N).
Once formed, the dative bond is an ordinary shared pair, so the ion has four identical N-H bonds and the 1+ charge is spread over the whole ion.
Result: The nitrogen lone pair forms a dative bond to H+; all four N-H bonds are then equivalent.
Typical mistakes
Active revision
Explain, in terms of what is broken, why silicon dioxide (a giant covalent solid) has a much higher melting point than carbon dioxide (a simple molecular solid).
Active recall
Recall the key points — then reveal.
Sources: AQA A-level Chemistry 7405 specification (AQA)
The four types of structure
A white solid melts at 993 C, does not conduct when solid, conducts when molten, and dissolves in water. Deduce and justify its structure and bonding.
The high melting point rules out simple molecular; it suggests a giant structure.
Conducting only when molten (not solid) is the signature of mobile ions freed on melting - characteristic of an ionic lattice.
Dissolving in water fits ionic (polar water surrounds the ions), confirming the deduction.
Result: The substance is a giant ionic solid: high melting point, conducts only when molten or aqueous, soluble in water.
Typical mistakes
Active revision
A solid has a very high melting point, does not dissolve in water and conducts electricity as a solid but not when its bonds are considered as localised. Identify and justify the type of structure. (Hint: consider graphite.)
Active recall
Recall the key points — then reveal.
Sources: AQA A-level Chemistry 7405 specification (AQA)
Tetrahedral methane
Shapes from electron-pair repulsion
Predict and explain the shape and bond angle of a water molecule, H2O.
Oxygen has 6 outer electrons; two form bonds to H, leaving two lone pairs, so there are 4 electron pairs (2 bonding, 2 lone).
Four pairs point to the corners of a tetrahedron, but only the two O-H bonds are 'seen', so the shape is bent (V-shaped).
The two lone pairs repel more strongly than the bonding pairs, squeezing the H-O-H angle from 109.5 down to 104.5.
Result: Water is bent with a bond angle of 104.5 degrees, because two lone pairs on oxygen repel the bonding pairs closer together.
Typical mistakes
Active revision
Predict the shape and bond angle of the ion, justifying your answer in terms of electron pairs.
Active recall
Recall the key points — then reveal.
Sources: AQA A-level Chemistry 7405 specification (AQA)
Hydrogen bonding between water molecules
Ammonia (NH3) boils at -33 C, whereas phosphine (PH3) boils at -88 C, even though PH3 has more electrons. Explain this.
PH3 molecules are held only by weak van der Waals and small dipole forces; NH3 molecules can hydrogen bond, because H is bonded to the small, very electronegative N with a lone pair.
Hydrogen bonds are much stronger than the van der Waals forces in PH3, despite PH3 having more electrons.
More energy is needed to overcome the hydrogen bonds in ammonia, so it boils at a higher temperature.
Result: Ammonia boils higher because it forms hydrogen bonds, which are stronger than the van der Waals forces holding phosphine together.
Typical mistakes
Active revision
Explain why the boiling point of water (100 C) is much higher than that of hydrogen sulfide (-60 C), even though both are Group 6 hydrides.
Active recall
Recall the key points — then reveal.
Sources: AQA A-level Chemistry 7405 specification (AQA)
References & sources
Department for Education